From: Paolo 'Blaisorblade' Giarrusso <blaisorblade@yahoo.it>

If enable is moved by GCC in a register its value may not be preserved after
coming back there with longjmp().  So, mark it as volatile to prevent this;
this is suggested (it seems) in info gcc, when it talks about -Wuninitialized.
 I re-read this and it seems to say something different, but I still believe
this may be needed.

Signed-off-by: Paolo 'Blaisorblade' Giarrusso <blaisorblade@yahoo.it>
Cc: Jeff Dike <jdike@addtoit.com>
Signed-off-by: Andrew Morton <akpm@osdl.org>
---

 arch/um/include/longjmp.h |    3 ++-
 1 files changed, 2 insertions(+), 1 deletion(-)

diff -puN arch/um/include/longjmp.h~uml-make-uml_setjmp-always-safe arch/um/include/longjmp.h
--- a/arch/um/include/longjmp.h~uml-make-uml_setjmp-always-safe
+++ a/arch/um/include/longjmp.h
@@ -12,7 +12,8 @@ extern void longjmp(jmp_buf, int);
 } while(0)
 
 #define UML_SETJMP(buf) ({ \
-	int n, enable;	   \
+	int n;	   \
+	volatile int enable;	\
 	enable = get_signals(); \
 	n = setjmp(*buf); \
 	if(n != 0) \
_